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There are more than 50,000 words in the
vocabulary. So let us truncate it to have only 10,000 most common words.
vocab_size = << your code comes here >>
Extract the top 10,000 most frequently occurring words from
vocabulary and store these words in
truncated_vocabulary list(let us use the list comprehension method to do so).
<< your code comes here >> = [ word for word, count in vocabulary.most_common()[:vocab_size]]
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