Python Dictionaries and Tuples

n the expression v = f(i), (i) represents the input argument or parameter that is passed to the function f().

The v represents the output or result of the function f(). After the function is called with the input argument (i), it performs some computation or processing and returns a value, which is assigned to the variable v. The specific meaning of v will depend on the function and its intended purpose.

r = []  -- Defines an empty list.

v = f(i) -- Accessing element at index i in type f

Hi Anagha

For free python course, there is no certificate provided

Regards

Hi,

I have reset your password, please try to login once again and let me know if it is working fine now. Also, this time try to type in the password instead of copy pasting it.

Thanks.

Hi, 

You can write something like:

if dict[key]==value:
    print(key)

Thanks.

Hi,

Please share the screenshot of where exactly you are facing the issue.

Thanks.

This comment has been removed.

Hi Nirav,

In Python, this is one way to initialize a list it is similar to 'list()'. So both 

r = [] 

and 

r = list()

are same.

So I think if this is a list object then `append` function will work to add a element in the list.

Hope this helps you. Happy learning :)

Hi Chitra,

You have to select the lines which you want to comment on, and then hit the `ctrl` and `/` on windows or Linux. if you are working on the Mac then you have to hit the `cmd` + `/`.

You can use the same keys to uncomment as well if you select the commented lines.

Hope this help.

Happy learning :)

P.S. I am sure you already look the jupyter notebook keyboard shortcuts(Help -> Keyboard shortcuts) which is actually fasten the development 

Hi,

Could you please give me more details about how you are creating a file, and how are you trying to run it?

Thanks.

Hi,

Dictionary keys should be unique.

Thanks.

Hi Chaitra,

Interesting question. Dictionary is like hashmap so it gives you the value at a key in O(1) time.

For your question, why do not you give it a shot yourself? :) Few ideas to solve this can be - Reverse the dictionary or use a dictionary comprehension to create a lookup dictionary and then use that to find the key from the value 

Hi,

For any doubts/queries, you can leave a comment below the respective tutorial and we will revert to you.

Thanks.

This comment has been removed.

Hi,

You can find our GitHub repository at the below link:

https://github.com/cloudxlab/ml

Also, you can clone our repository using the below command on a web console:

git clone https://github.com/cloudxlab/ml ~/ml

Thanks.

Hi,

Could you please tell me which part of the tutorial are you referring to?

Thanks.

Hi,

Good question!

You can try the following:

try:
    my_abs_path = my_file.resolve(strict=True)
except FileNotFoundError:
    # doesn't exist
else:
    # exists

You can go through the below link for more details:

https://stackoverflow.com/questions/82831/how-do-i-check-whether-a-file-exists-without-exceptions

Thanks.

Hi,

Please refer to this: https://stackoverflow.com/questions/1350671/inner-exception-with-traceback-in-python. Hope this helps.

Thanks.

Hi,

These are codes shown as examples, you do not need to replicate them. You will have numerous coding assignments as you move forward in this course. Also, if you want to view the codes shown in the lecture video, you can refer to our GitHub repository for the latest version of these codes from the below link:

https://github.com/cloudxlab/ml/tree/master/python

Thanks.

Hi,

We are iterating through the names and checking if a name is already present as a key in the counts dictionary. If no, a new key-value pair with the name as key and value as 1 is created. Else, the count of the name is increased by 1. Hope this helps.

Thanks.

Hi,

a is an empty list, but you're attempting to write to element [0] in the first iteration, which doesn't exist yet.

Try the following instead, to add a new element to the end of the list:

a.append(1)

Thanks.

Hi,

Could you please tell me where does it say "sq is not defined"?

Thanks.

Can you show me the code?

Hi,

Are you still facing this issue? If yes, then please share a screenshot.

Thanks.

Hi,

Are you still facing this issue?

Thanks.

Hi,

Instead of me answering this for you, let me help you finding the answer. Please create a list and then use the max() function on the same.

Thanks.

Hi,

Your password has been reset. Please re-try now.

Thanks.

Hi Syed,

Sorry for the inconvenience, i have reset your password, please try again.

Hi,

get method of a dictionary returns the value associated with the specified key. Here, counts.get(name,0) returns counts[name]; if that key doesn't't exist, then 0 will be returned. Thus, counts[name] = counts.get(name,0) +1 means, if the key is there, its values gets incremented by 1; else, count[name] becomes 0+1 which is 1. Hope this helps.

Thanks.

Hi,

Would suggest you to have a look at the answer.

Thanks.

Hi,

Try to stop your server(by clicking on control-panel option on top-right side of the notebook), then click on my server. After it connects, refresh your page. Hope this helps.

Thanks.

Hi,

We are passing the array to calculate the square of each item in the array and append the result.

Thanks.

Hi,

Have a look at this https://www.geeksforgeeks.org/mathematical-functions-in-python-set-3-trigonometric-and-angular-functions/.

Thanks.

Hi,

Try this:

c = dict()
names = ('name1','name1','name2','name1','name3','name2')
for name in names:
    c[name] = c.get(name,0)+1

Thanks.

Hi Kranti,

The x was a typo, so Sandeep just changed the name to f.

Thanks.

Hi,

Thanks for your feedback. We have similar plans to make these videos more accessible. We would definitely consider this during our future updates.

Thanks.

Hi Kranti,

It is returning False because y is of string type whereas there's nothing assigned to x and hence x and y are not equal.

Thanks and Regards,

Shubh Wadekar

Hi Kranti,

'housekeys' in mybag
The above command is just checking if it exists in the dictinary and as it exists in the dictionary, it's returning True.

Thanks and Regards,

Shubh Wadekar

Hi Kranti,

Can you share the screenshot of the error with your code?

Thanks and Regards,

Shubh Wadekar

Hi,

I could not find the same mentioned at 00:48:10 timestamp of the video. Could you please check and let me know if it is at any other location.

Thanks.

Hi,

Here we are saving a key, value tuple in this list and we are sorting based on that key.

Thanks.

Hi,

Good question!

A dynamic list in Python is a list which resizes everytime an element is appended to it.

Thanks.

Hi,

Would request you to refer to assessment 122.

Thanks.

Hi,

We do not have any provision for manual assessments. Would suggest you to post this on the discussion forum for peer review.

Thanks.

Hi,

Good question! Here's an example:

N = 4
print ("The reversed numbers are : ", end = "") 
for num in reversed(range(N + 1)) : 
    print (num, end = " ") 

Thanks.

Hi,

Very interesting question! Yes, we can have nested lambda functions. Here is an example:

f = lambda a = 8, b = 7:lambda c: a+b+c 
  
o = f() 
print(o(4)) 

Thanks.

Hi,

This is because print does not return any value but prints it. So it is returning None.

Thanks.

Hi,

It is always best practice to import modules at the starting/top of any program. However, one can also import inside a user-defined function.

Hope this helps. 

Thanks.

Hi Apratimkumar,

Try Python - Part I or follow this link: https://github.com/cloudxlab/ml/blob/master/python/Python%20-%20Part%20I.ipynb

Thanks

Hi,

Would suggest you to go through our Fair Usage Policy to know about the best practices on using our lab:

https://cloudxlab.com/faq/6/what-are-the-limits-on-the-usage-of-lab-or-what-is-the-fair-usage-policy-fup

Thanks.

Hi,

Your overall course progress is 32%, are you still facing this issue?

Thanks.

Hi,

Are you facing any challenges with this?

Thanks.

Hi,

You need to mention the path for the file simpleexp.py. Also, you can clone out github repository using the following command in a web console:

git clone https://github.com/cloudxlab/ml

Thanks.

Hi,

I checked from my end, you account is active and working fine. Would request you to type in your username and password instead of copy pasting them.

Thanks.

Hi,

This is the code for which assessment?

Thanks.

Hi,

You can, but password encryption algorithms require something more sophisticated than that.

Thanks.

Hi,

Could you please tell me which slides, or which part of the video are you referring to?

Thanks.

Hi,

Could you please tell me which slides, or which part of the video are you referring to?

Thanks.

Hi,

Our GitHub repository hosts all the latest notebooks that were referred in this course. You can clone the GitHub repository to access those notebooks in your lab using the following command (please try this command in the console and not the Jupyter notebook):

git clone https://github.com/cloudxla... ~/ml

If you want to know more about GitHub, you can follow the below link:
https://product.hubspot.com...
Thanks.

-- Rajtilak Bhattacharjee

Like the error statement, there is no function or variable called sq in the code

-- Praveen Pavithran

Last...line of the code will be displayed.

Jupyter prints the value for such statement

-- Praveen Pavithran

Rakhi,

Could you tell me why you need this tool for this assignment?

-- Praveen Pavithran

Hi,

Would request you to share a screenshot of your code and the error that you are getting.

Thanks.

-- Rajtilak Bhattacharjee

Hi,

The Jupyter notebook that opens on the right side of the topics are special notebooks for automated assessment by the playground. You cannot open a .py file on the right side, it would open in a new window.

Thanks.

-- Rajtilak Bhattacharjee

Hi,

Would request you to share a screenshot of your code and the error that you are getting.

Thanks.

-- Rajtilak Bhattacharjee

try below:


r = []
for i in range(5):
x = int(input('Input value: '))
r.append(x)
print (r)


Hi,

I am so sorry to hear that your XPs were deducted despite answering the questions correctly. Would request you to let us know when you know it is the correct answer but it is showing it has incorrect.

The XPs help you see the hints or answers as and when required.

Thanks.

-- Rajtilak Bhattacharjee

Hi,

You can create a 2D array with the following code:

rows, cols = (5, 5)
arr = [[0]*cols]*rows
print(arr)
Please note that a 2D array is one which has more than 1 row and more than 1 column.
Thanks.

-- Rajtilak Bhattacharjee

Hi,

The *return* statement terminates the execution of a *function* and *returns* control to the calling *function*. Execution resumes in the calling *function* at the point immediately following the call. A *return* statement
can also *return* a value to the calling *function*.

Thanks.

-- Rajtilak Bhattacharjee

Hi,

*Lambda functions: *are operator can have any number of arguments, but it can have only one expression. It cannot contain any statements and it returns a function object which can be assigned to any variable. They can be used in the block they were created.

*def functions:* Functions help break our program into smaller and modular chunks. As our program grows larger and larger, functions make it more organized and manageable. They can be called and used anywhere we want.
Hope that answers your queries.

Thanks.

-- Rajtilak Bhattacharjee

Hi,

Would request you to follow the method give in this link:
https://discuss.cloudxlab.c...
Thanks.

-- Rajtilak Bhattacharjee

Hi,

In the first example, you are getting a handle to both the key, and the value. However, in the second one you are only printing the key (the value gets printed automatically with it).

Thanks.

-- Rajtilak Bhattacharjee

Hi Souvik,

Would request you to check the minimum requirements on the GitHub website and check if it matches your system.

Thanks.

-- Rajtilak Bhattacharjee

Hi,

The link to the codes in our repository are given just below the slides. Here's the link:

https://github.com/cloudxla...

Thanks.

-- Rajtilak Bhattacharjee

Hi Sumit,

Since you are using elif, the return command below that should be indented to the right.

Thanks.

-- Rajtilak Bhattacharjee

Hi Sumit,

Are you getting any error with this code? If yes, then would request you to share a screenshot of your code and the error that you are getting,

Thanks.

-- Rajtilak Bhattacharjee

Hi Sumit,

As mentioned in the course, every code that we show here is there in our GitHub repository. You need to clone it here using the following command:
git clone https://github.com/cloudxla...

If you want, you can even fork it in your personal GitHub account.

Thanks.

-- Rajtilak Bhattacharjee

Hi,

We do not have a separate session on lambda function, however, let me explain it for you. A lambda function is a small anonymous function. A lambda function can take any number of arguments, but can only have one expression.

Following are a couple of examples:

x = lambda a : a + 10

x = lambda a, b, c : a + b + C

x = lambda a, b : a * b

Thanks.

-- Rajtilak Bhattacharjee

Hi,

This is because you are mentioning the first index by using [0].

Thanks.

-- Rajtilak Bhattacharjee

Hi,

You can convert a list into a dictionary like the following:

def Convert(a):
it = iter(lst)
res_dct = dict(zip(it, it))
return res_dct

# Driver code
lst = ['a', 1, 'b', 2, 'c', 3]
print(Convert(lst))

A list stores one element at a time, whereas a dictionary stores a key value pair. We need to keep that in mind while converting them.

Thanks.

-- Rajtilak Bhattacharjee

Hi,

You need to create a lambda function that would calculate the cube, and then pass that function as an argument to the function.

Thanks.

-- Rajtilak Bhattacharjee

Hi, Nischal.

You are using retv=f(i), this for every for loop this will be going to update the variable retv and at last you will be only remaining with the last value that is 16.
But you would like to add every value to the list you need to use append retv.append(f(i)).
Now you will be getting all the squares of the elements inside the list.
All the best!

-- Satyajit Das

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Hi Mohini,

If you look at the syntax of a loop statement, it itself contains the type it needs to loop with. For example, when we say

for val in array:
print(val)
we are already telling the loop that we need to iterate an array using it's basic component, which is it's elements. So when we tell the loop to iterate a line using it's basic elements, it understand that we want to loop using words. The syntax of the loop gives it that information.
Thanks.

-- Rajtilak Bhattacharjee

Hi, Monika.

You can any python file from the terminal using command "python first.py ".
If you are using python3 version then python3 first.py.

All the best!

Hi, Karthik.
Tuple comparison is done elements by elements wise, if 1st is True, then it gives True. If rest is false then it is okay, but the first elements must be True then only True otherwise False.
try this (3,5,3) < (2,3,1) , (1,5,3) < (2,3,1) etc.
All the best!

Hi, Sourabh.

It is giving [6, 9, 15].
Can you rerun the code
v=f(i)
r.append(v) should be kept inside the for loop.

All the best!

Hi, Vivek.

Here are the Cloudxlab github repository.
================================
1) https://github.com/cloudxla...
2) https://github.com/cloudxla...
3) https://github.com/singhabh...

All the best!

Hi, RK.

I understand that you are trying to find the square root of the list if number passed but you have not defined the sq, you need to write a separate logic for this. the you can pass this as argument.
Below code I have modified for you.

import math
def sqrtf(a):
rt=[]
for i in a:
v=math.sqrt(i)
rt.append(v)
return rt

All the best!

Yes. I agree with you. Previously i have raised issue but no one has not response.

'None' can be added as a key value in dictionary. 'Null' can't be added as a key value in dictionary.

eg:
dictn = {'one': 4, None:2}
print(dictn)

a = dictn.get(None,0) + 1
a

Output :
{'one': 4, None: 2}
3

Hi, Prashant.

Please check the correct path of the file.

All the best.

Hi Sai, In Jupyter, we can only use %run

Hi Eduardo, thank you for a constructive feedback. The Instructor has been communicated to.